Question:
If, find at a point where y = 3.
If, find at a point where y = 3.
Updated On: Jun 23, 2024
- (A) 3
- (B) -3
- (C) -6
- (D) -9
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Explanation:
Now putting y = 3 we get Hence, the correct option is (B).
Now putting y = 3 we get Hence, the correct option is (B).
Was this answer helpful?
0
0
Top MHT CET Mathematics Questions
- The line $5x + y - 1 = 0$ coincides with one of the lines given by $5x^2 + xy - kx - 2y + 2 = 0 $ then the value of k is
- If $\int\frac{f\left(x\right)}{log \left(sin\,x\right)}dx = log\left[log\,sin\,x\right]+c$ then $f\left(x\right)=$
- If $\int\limits^{K}_0 \frac{dx}{2 + 18 x^2} = \frac{\pi}{24}$, then the value of K is
- If $\int^{\pi/2}_{0} \log\cos x dx =\frac{\pi}{2} \log\left(\frac{1}{2}\right)$ then $ \int^{\pi/2}_{0} \log\sec x dx = $
- The point on the curve $y = \sqrt{x - 1}$ where the tangent is perpendicular to the line $2x + y - 5 = 0 $ is
View More Questions
Top MHT CET integral Questions
- $ \int\left[sin \left(log\,x\right)+cos\left(log\,x\right)\right]dx $ is equal to
- $ \int e^{x} \frac{\left(x-1\right)}{x^{2}} dx $ is equal to
- $ \int\limits_{5}^{10} \frac{1}{\left(x-1\right)\left(x-2\right)}dx $ is equal to
- Cards numbered from to are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible both by and ?
- Maximam value of y Subject to : at:
View More Questions
Top MHT CET Questions
- During r- DNA technology, which one of the following enzymes is used for cleaving DNA molecule ?
- In non uniform circular motion, the ratio of tangential to radial acceleration is (r = radius of circle, $v =$ speed of the particle, $\alpha =$ angular acceleration)
- The temperature of $32^{\circ}C$ is equivalent to
- The line $5x + y - 1 = 0$ coincides with one of the lines given by $5x^2 + xy - kx - 2y + 2 = 0 $ then the value of k is
- The heat of formation of water is $ 260\, kJ $ . How much $ H_2O $ is decomposed by $ 130\, kJ $ of heat ?
View More Questions