Question:

If \( x + y = 1 \), then \[ \sum_{r=0}^{n} r^2 \cdot n C_r x^r y^{n-r} \quad \text{is equal to:} \]

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When solving summation problems with binomial coefficients, look for standard identities to simplify the expression.
Updated On: Apr 22, 2026
  • \( nxy \)
  • \( n x(x + y n) \)
  • \( n x (x + y) \)
  • None of these
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The Correct Option is C

Solution and Explanation

Step 1: Use the binomial expansion.
We are asked to evaluate the sum: \[ \sum_{r=0}^{n} r^2 \cdot n C_r x^r y^{n-r} \] Given \( x + y = 1 \), we can expand this sum using the binomial expansion.

Step 2: Apply the identity for binomial sums.

Use the identity for sums involving binomial coefficients and powers: \[ \sum_{r=0}^{n} r^2 \cdot n C_r x^r y^{n-r} = n x(x + y) \] Substituting \( x + y = 1 \): \[ = n x (x + y) = n x \] Thus, the correct answer is \( n x (x + y) \), corresponding to option (C).
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