Question:

If \[ x+\frac1x=3, \] then the value of \[ x^2+\frac1{x^2} \] is:

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Memorize the identity \[ \left(x+\frac1x\right)^2 = x^2+\frac1{x^2}+2. \] It is one of the most frequently used identities in algebra.
Updated On: Oct 5, 2026
  • \(5\)
  • \(7\)
  • \(9\)
  • \(11\)
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The Correct Option is B

Solution and Explanation

Concept: Questions involving expressions such as \[ x+\frac1x \] are usually solved using algebraic identities. Instead of finding the value of \(x\), we manipulate the given expression to obtain the required expression. A very important identity is \[ \left(x+\frac1x\right)^2 = x^2+\frac1{x^2}+2. \] This identity directly connects the given information with the required quantity.

Step 1: Write the given condition. \[ x+\frac1x=3. \]

Step 2: Square both sides. \[ \left(x+\frac1x\right)^2 = 3^2. \] \[ = 9. \]

Step 3: Apply the standard identity. \[ x^2+\frac1{x^2}+2 = 9. \]

Step 4: Solve for the required expression. Subtracting \(2\) from both sides, \[ x^2+\frac1{x^2} = 9-2. \] \[ = 7. \]

Step 5: Verification. Substituting the obtained value into the identity confirms that \[ 7+2=9. \] The condition is satisfied exactly.

Step 6: Final Conclusion. \[ \boxed{x^2+\frac1{x^2}=7} \] Hence the correct answer is \[ \boxed{\text{Option (B)}}. \]
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