Question:
If ₀ⁿ [x]dx = 66, then n=
If ₀ⁿ [x]dx = 66, then n=
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₀ⁿ [x]dx=(n(n-1))/(2).
Updated On: Mar 17, 2026
- 24
- 9
- 12
- 7
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The Correct Option is C
Solution and Explanation
₀ⁿ [x]dx = =₀ⁿ⁻¹ k = (n(n-1))/(2)
Given:
(n(n-1))/(2)=66 n²-n-132=0
n=12
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