Step 1: Use identity to relate \(x^4 + y^4\) with \(x^2 + y^2\) and \(xy\). We start with the identity: \[ x^4 + y^4 = (x^2 + y^2)^2 - 2x^2y^2 \] Step 2: Use the given: \[ x^2 + y^2 = 25, \quad xy = 12 \Rightarrow x^2y^2 = (xy)^2 = 144 \] Step 3: Substitute in the identity: \[ x^4 + y^4 = (25)^2 - 2(144) = 625 - 288 = 337 \].
| List-I | List-II | ||
|---|---|---|---|
| (A) | $f(x) = \frac{|x+2|}{x+2} , x \ne -2 $ | (I) | $[\frac{1}{3} , 1 ]$ |
| (B) | $(x)=|[x]|,x \in [R$ | (II) | Z |
| (C) | $h(x) = |x - [x]| , x \in [R$ | (III) | W |
| (D) | $f(x) = \frac{1}{2 - \sin 3x} , x \in [R$ | (IV) | [0, 1) |
| (V) | { -1, 1} | ||
| List I | List II | ||
|---|---|---|---|
| (A) | $\lambda=8, \mu \neq 15$ | 1. | Infinitely many solutions |
| (B) | $\lambda \neq 8, \mu \in R$ | 2. | No solution |
| (C) | $\lambda=8, \mu=15$ | 3. | Unique solution |