Question

If wavelengths of visible rays, microwaves and X-rays are $\lambda_v$, $\lambda_m$ and $\lambda_x$ respectively. Then out of the following which relation is correct one?

• A. $\lambda_m>\lambda_v>\lambda_x$
• B. $\lambda_v>\lambda_m>\lambda_x$
• C. $\lambda_m<\lambda_v<\lambda_x$
• D. $\lambda_v = \lambda_m = \lambda_x$

Hint:

Remember: \textbf{R}ich \textbf{M}en \textbf{I}n \textbf{V}egas \textbf{U}se \textbf{X}-ray \textbf{G}oggles. This covers Radio, Micro, Infra, Visible, UV, X-ray, Gamma in order of decreasing wavelength.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
The Electromagnetic Spectrum is arranged by either increasing frequency or increasing wavelength. There is an inverse relationship between frequency and wavelength.
Step 2: Detailed Explanation:
Order of the EM spectrum (from longest wavelength to shortest): 1. Radio waves 2. Microwaves ($\lambda_m$) 3. Infrared 4. Visible light ($\lambda_v$) 5. Ultraviolet 6. X-rays ($\lambda_x$) 7. Gamma rays Therefore, $\lambda_m$ (microwaves) is larger than $\lambda_v$ (visible), which is larger than $\lambda_x$ (X-rays).
Step 3: Final Answer:
The correct relation is $\lambda_m>\lambda_v>\lambda_x$.