Question:
A charged particle oscillates about its mean equilibrium position with a frequency of $8 \times 10^9$ Hz. What is the frequency of the electromagnetic waves produced by the oscillator?
A charged particle oscillates about its mean equilibrium position with a frequency of $8 \times 10^9$ Hz. What is the frequency of the electromagnetic waves produced by the oscillator?
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This principle is the basis of how radio transmitters work—electrons are made to oscillate at a specific frequency in an antenna to broadcast waves of that same frequency.
Updated On: Apr 1, 2026
- $4 \times 10^9$ Hz
- $1.6 \times 10^{10}$ Hz
- $8 \times 10^9$ Hz
- $2 \times 10^9$ Hz
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
According to Maxwell's theory, an accelerating or oscillating charge produces electromagnetic waves.
Step 2: Detailed Explanation:
The frequency of the electromagnetic wave produced is exactly equal to the frequency with which the charged particle oscillates. Since the particle oscillates at $8 \times 10^9$ Hz, the resulting EM wave will have the same frequency.
Step 3: Final Answer:
The frequency of the EM waves is $8 \times 10^9$ Hz.
According to Maxwell's theory, an accelerating or oscillating charge produces electromagnetic waves.
Step 2: Detailed Explanation:
The frequency of the electromagnetic wave produced is exactly equal to the frequency with which the charged particle oscillates. Since the particle oscillates at $8 \times 10^9$ Hz, the resulting EM wave will have the same frequency.
Step 3: Final Answer:
The frequency of the EM waves is $8 \times 10^9$ Hz.
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