Question:

If \(\vec{r}=4\hat{i}+2\hat{j}+7\hat{k}+\lambda (3\hat{i}-5\hat{k})\) is the vector equation of the line passing through \((7,2,2)\), where \(\lambda\) is parameter, then the value of \(\lambda\) is...

Show Hint

Equate the position vector of the given point with the line equation and compare components.
Updated On: Nov 12, 2026
  • \(-1\)
  • \(2\)
  • \(-2\)
  • \(1\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
The point \((7,2,2)\) has position vector \(7\hat{i}+2\hat{j}+2\hat{k}\). It lies on the line for some \(\lambda\).

Step 2: Equate
\(4\hat{i}+2\hat{j}+7\hat{k}+\lambda(3\hat{i}-5\hat{k})=7\hat{i}+2\hat{j}+2\hat{k}\).

Step 3: Compare Components
\(\hat{i}\): \(4+3\lambda=7\Rightarrow\lambda=1\).
\(\hat{k}\): \(7-5\lambda=2\Rightarrow\lambda=1\).

Final Answer:
The value of lambda is 1. \[ \boxed{\text{(D) }1} \]
Was this answer helpful?
0
0