Step 1: Understanding the Question:
The question asks us to find the sum of scalars $x$ and $y$ such that the vector $\vec{a}$ is expressed as a linear combination of the vectors $\vec{b}$ and $\vec{c}$ via the relation $\vec{a} = x\vec{b} + y\vec{c}$.
Step 2: Key Formula or Approach:
We substitute the given component forms of vectors $\vec{a}$, $\vec{b}$, and $\vec{c}$ into the linear equation. By equating the corresponding coefficients of $\hat{i}$, $\hat{j}$, and $\hat{k}$ from both sides, we form a system of simultaneous linear equations to determine $x$ and $y$.
Step 3: Detailed Explanation:
Substitute the vectors into the relation $\vec{a} = x\vec{b} + y\vec{c}$:
$$4\hat{i} + 13\hat{j} - 18\hat{k} = x(\hat{i} - 2\hat{j} + 3\hat{k}) + y(2\hat{i} + 3\hat{j} - 4\hat{k})$$
$$4\hat{i} + 13\hat{j} - 18\hat{k} = (x + 2y)\hat{i} + (-2x + 3y)\hat{j} + (3x - 4y)\hat{k}$$
Equating components on both sides gives three separate linear equations:
align
x + 2y &= 4
-2x + 3y &= 13
3x - 4y &= -18
align
Let's solve equations (1) and (2). From equation (1), isolate $x$:
$$x = 4 - 2y$$
Substitute this value into equation (2):
$$-2(4 - 2y) + 3y = 13$$
$$-8 + 4y + 3y = 13$$
$$7y = 21 \implies y = 3$$
Substitute $y = 3$ back into the expression for $x$:
$$x = 4 - 2(3) = 4 - 6 = -2$$
Let's verify these values using equation (3):
$$\text{LHS} = 3(-2) - 4(3) = -6 - 12 = -18 = \text{RHS}$$
The values are consistent. Now calculate $x + y$:
$$x + y = -2 + 3 = 1$$
Step 4: Final Answer:
The value of $x + y$ is $1$, which corresponds to option (D).