Question:

If three vertices of a regular hexagon are chosen at random, then the chance that they form an equilateral triangle is

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Count favourable combinations carefully in geometric probability.
Updated On: Mar 19, 2026
  • \(\dfrac{1}{3}\)
  • \(\dfrac{1}{5}\)
  • \(\dfrac{1}{10}\)
  • (1)/(2)
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The Correct Option is C

Solution and Explanation

Total ways: ⁶C₃=20 Favourable equilateral triangles: 2 Probability: (2)/(20)=(1)/(10)
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