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if three vertices of a regular hexagon are chosen
Question:
If three vertices of a regular hexagon are chosen at random, then the chance that they form an equilateral triangle is
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Count favourable combinations carefully in geometric probability.
BITSAT - 2020
BITSAT
Updated On:
Mar 19, 2026
\(\dfrac{1}{3}\)
\(\dfrac{1}{5}\)
\(\dfrac{1}{10}\)
(1)/(2)
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The Correct Option is
C
Solution and Explanation
Total ways: ⁶C₃=20 Favourable equilateral triangles: 2 Probability: (2)/(20)=(1)/(10)
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