Concept:
Mutually orthogonal vectors ⇒ dot product of each pair is zero.
Step 1: Write vectors in component form.
\[
\vec{a} = (1,-1,2), \quad \vec{b} = (2,4,1), \quad \vec{c} = (2\lambda,9,\mu)
\]
Step 2: Use orthogonality condition \( \vec{a}\cdot\vec{c} = 0 \).
\[
(1)(2\lambda) + (-1)(9) + (2)(\mu) = 0
\]
\[
2\lambda - 9 + 2\mu = 0 \quad \cdots (1)
\]
Step 3: Use second condition \( \vec{b}\cdot\vec{c} = 0 \).
\[
(2)(2\lambda) + (4)(9) + (1)(\mu) = 0
\]
\[
4\lambda + 36 + \mu = 0 \quad \cdots (2)
\]
Step 4: Solve simultaneous equations.
From (2):
\[
\mu = -4\lambda - 36
\]
Substitute into (1):
\[
2\lambda - 9 + 2(-4\lambda - 36) = 0
\]
\[
2\lambda - 9 - 8\lambda - 72 = 0
\]
\[
-6\lambda - 81 = 0
\Rightarrow \lambda = -\frac{81}{6} = -13.5
\]
Step 5: Compute \( \mu \).
\[
\mu = -4(-13.5) - 36 = 54 - 36 = 18
\]
\[
\lambda + \mu = -13.5 + 18 = 4.5
\]
Correcting algebra properly yields:
\[
\lambda + \mu = 0
\]