Question:
If the two sources of light emit waves of different amplitudes and interfere then
If the two sources of light emit waves of different amplitudes and interfere then
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Destructive interference gives zero intensity only when the two amplitudes are equal.
Updated On: Nov 13, 2026
- there is some intensity of light in the region of destructive interference.
- fringe width is less.
- brightness of fringes is less.
- fringes disappear after short time.
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
The resultant intensity is \(I=I_1+I_2+2\sqrt{I_1I_2}\cos\phi\).
Step 2: Minimum intensity
At destructive interference \(\cos\phi=-1\), so \(I_{min}=(\sqrt{I_1}-\sqrt{I_2})^{2}\).
If the amplitudes are different, \(I_{min}\neq 0\).
Step 3: Compare the options
So some light is still present in the region of destructive interference, which is option (A).
Fringe width depends on wavelength, distance and slit separation, not on amplitude, and the fringes do not disappear.
Final Answer:
Some intensity remains in the region of destructive interference. \[ \boxed{\text{(A) }\text{there is some intensity of light in the region of destructive interference.}} \]
The resultant intensity is \(I=I_1+I_2+2\sqrt{I_1I_2}\cos\phi\).
Step 2: Minimum intensity
At destructive interference \(\cos\phi=-1\), so \(I_{min}=(\sqrt{I_1}-\sqrt{I_2})^{2}\).
If the amplitudes are different, \(I_{min}\neq 0\).
Step 3: Compare the options
So some light is still present in the region of destructive interference, which is option (A).
Fringe width depends on wavelength, distance and slit separation, not on amplitude, and the fringes do not disappear.
Final Answer:
Some intensity remains in the region of destructive interference. \[ \boxed{\text{(A) }\text{there is some intensity of light in the region of destructive interference.}} \]
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