Question:
If the sum of odd-numbered terms and even-numbered terms in the expansion of (x+a)ⁿ are A and B respectively, then the value of (x²-a²)ⁿ is
If the sum of odd-numbered terms and even-numbered terms in the expansion of (x+a)ⁿ are A and B respectively, then the value of (x²-a²)ⁿ is
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Odd–even term sums relate to (x± a)ⁿ.
Updated On: Mar 19, 2026
- \(A^2-B^2\)
- \(A^2+B^2\)
- \(4AB\)
- None
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Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Using binomial expansion properties:
A-B=(x-a)ⁿ, A+B=(x+a)ⁿ
Thus,
(x²-a²)ⁿ=(A-B)(A+B)=A²-B²
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