Concept:
For a conditional statement \(P \rightarrow Q\):
\[
\text{It is False only when } P = T \text{ and } Q = F
\]
Also remember:
- Conjunction \(P \wedge Q\) is True only when both are True.
- Disjunction \(P \vee Q\) is False only when both are False.
Step 1: {Use the condition for implication to be false.}
Given:
\[
(p \wedge q) \rightarrow (r \vee \neg s) \equiv F
\]
An implication is False only when:
\[
(p \wedge q) = T \quad \text{and} \quad (r \vee \neg s) = F
\]
Step 2: {Evaluate \(p\) and \(q\).}
For the conjunction:
\[
(p \wedge q) = T
\]
both statements must be True:
\[
p = T, \quad q = T
\]
Step 3: {Evaluate \(r\) and \(s\).}
For the disjunction:
\[
(r \vee \neg s) = F
\]
both components must be False:
\[
r = F
\]
\[
\neg s = F \Rightarrow s = T
\]
Step 4: {Write the final truth values.}
\[
(p,q,r,s) = (T,\,T,\,F,\,T)
\]
Step 5: {Conclusion.}
Thus, the required truth values are:
\[
T,\,T,\,F,\,T
\]