Question:

Identify the truth value of the statement pattern \( (p \land \sim q) \rightarrow r \).

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An implication \(p \rightarrow q\) is false only when \(p\) is true and \(q\) is false; in all other cases it is true.
Updated On: Apr 15, 2026
  • Tautology
  • Contradiction
  • Contingency
  • None of these
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The Correct Option is C

Solution and Explanation

Concept: In propositional logic:
  • Tautology: A statement that is always true.
  • Contradiction: A statement that is always false.
  • Contingency: A statement that is sometimes true and sometimes false.
The implication \( p \rightarrow q \) is false only when \( p \) is true and \( q \) is false.
Step 1: {Construct the truth table.} \[ \begin{array}{c|c|c|c|c} p & q & r & p \land \sim q & (p \land \sim q) \rightarrow r
\hline T & T & T & F & T
T & T & F & F & T
T & F & T & T & T
T & F & F & T & F
F & T & T & F & T
F & T & F & F & T
F & F & T & F & T
F & F & F & F & T \end{array} \]
Step 2: {Analyze the final column.} The final column contains both \(T\) and \(F\). Thus, the statement is sometimes true and sometimes false. \[ \therefore \text{The statement is a Contingency.} \]
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