Question:

If the roots of $x^2 + ax + 9 = 0$ are complex, then

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For quadratic $ax^2+bx+c=0$, roots are complex if $b^2-4ac<0$.
Updated On: Apr 8, 2026
  • $a<6$
  • $a<-6$
  • $|a|<6$
  • $|a|>6$
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
For a quadratic equation $x^2 + ax + 9 = 0$, roots are complex if discriminant $D<0$.
Step 2: Detailed Explanation:
Discriminant $D = a^2 - 4 \times 1 \times 9 = a^2 - 36$.
For complex roots: $a^2 - 36<0 \Rightarrow a^2<36 \Rightarrow |a|<6$.
Step 3: Final Answer:
The condition is $|a|<6$.
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