Question

If the product of roots of the equation $mx^2 + 6x + (2m-1) = 0$ is $-1$, then the value of m is

• A. $1$
• B. $-1$
• C. $\frac{1}{3}$
• D. $-\frac{1}{3}$

Hint:

For $ax^2+bx+c=0$, product = $c/a$.

Answer 1

The Correct Option is D

Step 1: Product of roots = $\frac{2m-1}{m} = -1$.}
Step 2: $2m-1 = -m \Rightarrow 3m = 1 \Rightarrow m = \frac{1}{3}$.}