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if the points 1 1 and 3 0 1 are equidistant from t
Question:
If the points \((1,1,μ)\) and \((-3,0,1)\) are equidistant from the plane \(\overset{⃗}{r}\cdot (3\hat{i}+4\hat{j}-12\hat{k})+13 = 0\), then the value of \(μ\) are
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Set the two distances from the plane equal.
MHT CET - 2026
MHT CET
Updated On:
Oct 1, 2026
\(1,\frac{-7}{3}\)
\(1,\frac{7}{3}\)
\(-1,\frac{7}{3}\)
\(1,\frac{3}{7}\)
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The Correct Option is
B
Solution and Explanation
Step 1: Plane in Cartesian form
\(3x+4y-12z+13=0\) and \(\sqrt{9+16+144}=13\).
Step 2: Distance of \((-3,0,1)\)
\(\frac{|-9+0-12+13|}{13}=\frac{8}{13}\).
Step 3: Distance of \((1,1,\mu)\)
\(\frac{|3+4-12\mu+13|}{13}=\frac{|20-12\mu|}{13}\).
Step 4: Equate
\(|20-12\mu|=8\) gives \(12\mu=12\) or \(12\mu=28\), so \(\mu=1\) or \(\frac73\). Option (B).
Final Answer:
\(\mu=1,\frac73\), option (B). \[ \boxed{\text{(B)}} \]
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