Question:
If the osmotic pressure of cane sugar solution is 2.46 atm at 27°C, then what is the concentration (in mol L\(^{-1}\)) of the solution (R = 0.0821 L atm mol\(^{-1}\) K\(^{-1}\))
If the osmotic pressure of cane sugar solution is 2.46 atm at 27°C, then what is the concentration (in mol L\(^{-1}\)) of the solution (R = 0.0821 L atm mol\(^{-1}\) K\(^{-1}\))
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Remember that osmotic pressure can help calculate concentration when dealing with colligative properties like osmotic pressure.
Updated On: Mar 18, 2026
- 0.1
- 0.2
- 0.01
- 0.02
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The Correct Option is A
Solution and Explanation
The formula for osmotic pressure is given by:
\(\Pi = \frac{nRT}{V}\)
Where \(\Pi\) is the osmotic pressure, \(n\) is the number of moles of solute, \(R\) is the ideal gas constant, \(T\) is the temperature, and \(V\) is the volume of the solution. Rearranging to find concentration:
\[\text{Concentration} = \frac{\Pi}{RT}\]
Substitute the known values to find the concentration.
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