Question:

If the nucleus \(X^{240}\), initially at rest, splits into two daughter nuclei \(Y^{100}\) and \(Z^{140}\), then the ratio of the kinetic energies of \(Y\) and \(Z\) is

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In nuclear fission or decay problems, use conservation of momentum to relate velocities. The kinetic energy ratio of daughter nuclei is inversely proportional to their mass ratio: \[ \frac{K_Y}{K_Z} = \frac{m_Z}{m_Y} \]
Updated On: May 5, 2026
  • \(5:7\)
  • \(7:5\)
  • \(1:1\)
  • \(49:25\)
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The Correct Option is B

Solution and Explanation

Step 1: Conservation of momentum

\[ m_Y v_Y = m_Z v_Z \]

\[ \frac{v_Y}{v_Z} = \frac{m_Z}{m_Y} \]

Step 2: Kinetic energy relation

\[ K = \frac{1}{2} m v^2 \]

\[ \frac{K_Y}{K_Z} = \frac{m_Y v_Y^2}{m_Z v_Z^2} \]

Step 3: Substitute velocity ratio

\[ \frac{K_Y}{K_Z} = \frac{m_Y}{m_Z} \left(\frac{m_Z}{m_Y}\right)^2 \]

\[ = \frac{m_Z}{m_Y} \]

Step 4: Substitute values

\[ \frac{K_Y}{K_Z} = \frac{140}{100} = \frac{7}{5} \]

Final Answer: \( 7:5 \)

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