Question:

If the lines \(p_1x+q_1y=1\), \(p_2x+q_2y=1\) and \(p_3x+q_3y=1\) are concurrent, then the points \((p_1,q_1), (p_2,q_2)\) and \((p_3,q_3)\) are

Show Hint

Concurrent lines \(\Rightarrow\) linear dependence of coefficients.
Updated On: Mar 23, 2026
  • collinear
  • form an equilateral triangle
  • form a scalene triangle
  • form a right angled triangle
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation


Step 1:
Concurrency implies the determinant of coefficients is zero.
Step 2:
Hence \((p_i,q_i)\) satisfy a linear relation.
Step 3:
Therefore the points are collinear.
Was this answer helpful?
0
0