Question

If the initial velocity of projection be doubled, keeping the angle of projection same, the maximum height reached by it will

• A. remain the same
• B. be doubled
• C. become four times
• D. be halved

Hint:

Maximum height of a projectile is proportional to the square of the initial speed for a fixed angle of projection.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
For a projectile the maximum height is \(H=\dfrac{u^{2}\sin^{2}\theta}{2g}\).

Step 2: Apply the Condition
The angle \(\theta\) and \(g\) stay the same, so \(H\propto u^{2}\).

Step 3: Calculation
If \(u\) becomes \(2u\), then \(H'=\dfrac{(2u)^{2}\sin^{2}\theta}{2g}=4H\).

Final Answer:
The maximum height becomes four times. \[ \boxed{\text{(C) }\text{become four times}} \]