Step 1: Interpreting the Question:
The phrase "decay from 20% to 80%" refers to the
percentage of the substance that has decayed.
- Initial state (20% decayed): Amount remaining $N_1 = 100% - 20% = 80%$ of $N_0$.
- Final state (80% decayed): Amount remaining $N_2 = 100% - 80% = 20%$ of $N_0$.
We need to find the time taken for the remaining amount to decrease from 80% to 20%.
Step 2: Calculating Number of Half-Lives:
Let's see the decay progression:
$80% \xrightarrow{T_{1/2}} 40% \xrightarrow{T_{1/2}} 20%$.
This transition takes exactly 2 half-lives.
Step 3: Calculating Time:
Half-life ($T_{1/2}$) = 10 minutes.
Total time $t = 2 \times T_{1/2} = 2 \times 10 = 20$ minutes.
Step 4: Final Answer:
The time taken is 20 minutes.