Question:

If the field of a synchronous motor is under excited. The power factor will be :

Show Hint

Synchronous motor excitation and power factor: \[ \text{Under excited} \rightarrow \text{Lagging PF} \] \[ \text{Normally excited} \rightarrow \text{Unity PF} \] \[ \text{Over excited} \rightarrow \text{Leading PF} \]
Updated On: May 22, 2026
  • zero
  • unity
  • lagging
  • leading
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Concept: The power factor of a synchronous motor depends upon field excitation.
• Under excitation \(\rightarrow\) lagging power factor
• Normal excitation \(\rightarrow\) unity power factor
• Over excitation \(\rightarrow\) leading power factor This property makes synchronous motors useful for power factor correction.

Step 1:
Understanding under excitation. Under excitation means: \[ E_f<V \] where:
• \(E_f\) = internal generated EMF,
• \(V\) = supply voltage. In this condition the motor draws reactive power from the supply.

Step 2:
Effect on current phase angle. Because reactive power is absorbed: \[ \text{Current lags voltage} \] Hence the motor behaves like an inductive load.

Step 3:
Understanding power factor behavior. Therefore: \[ \text{Under excited synchronous motor} \rightarrow \text{Lagging power factor} \]

Step 4:
Checking other options.
• Zero power factor \(\rightarrow\) Incorrect
• Unity power factor \(\rightarrow\) Occurs at normal excitation
• Lagging power factor \(\rightarrow\) Correct
• Leading power factor \(\rightarrow\) Occurs under over excitation

Step 5:
Selecting the correct answer. Hence the correct option is: \[ \boxed{(3)\; \text{lagging}} \]
Was this answer helpful?
0
0