If the equilibrium constant for \(\mathrm{A \rightleftharpoons B + C}\) is \(K_{eq}^{(1)}\) and that of \(\mathrm{B + C \rightleftharpoons P}\) is \(K_{eq}^{(2)}\), the equilibrium constant for \(\mathrm{A \rightleftharpoons P}\) is :
Show Hint
- \(\dfrac{K_{eq}^{(1)}}{K_{eq}^{(2)}}\)
- \(K_{eq}^{(1)} + K_{eq}^{(2)}\)
- \(K_{eq}^{(2)} - K_{eq}^{(1)}\)
- \(K_{eq}^{(1)}\,K_{eq}^{(2)}\)
The Correct Option is D
Solution and Explanation
Adding the two reactions \(\mathrm{A \rightleftharpoons B + C}\) and \(\mathrm{B + C \rightleftharpoons P}\) gives \(\mathrm{A \rightleftharpoons P}\) (B and C cancel).
\(K = \dfrac{[P]}{[A]} = \dfrac{[B][C]}{[A]} \times \dfrac{[P]}{[B][C]} = K_{eq}^{(1)} K_{eq}^{(2)}\).
Answer: (4) \(K_{eq}^{(1)}\,K_{eq}^{(2)}\)
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