Question:
If the energy of an electron in the first Bohr orbit of the H-atom is \(-2.18\times 10^{-18}\) J then the energy of the electron in the second orbit will be
If the energy of an electron in the first Bohr orbit of the H-atom is \(-2.18\times 10^{-18}\) J then the energy of the electron in the second orbit will be
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Use $E_n=\frac{E_1}{n^2}$.
Updated On: Oct 1, 2026
- \(-2.18\times 10^{-18}\) J
- \(-4.36\times 10^{-18}\) J
- \(-0.545\times 10^{-18}\) J
- \(-0.273\times 10^{-18}\) J
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The Correct Option is C
Solution and Explanation
Step 1: Formula
\(E_n=-\frac{2.18\times10^{-18}}{n^2}\) J.
Step 2: Substitute
For \(n=2\): \(E_2=\frac{-2.18\times10^{-18}}{4}=-0.545\times10^{-18}\) J. Option (C).
Final Answer:
\(E_2=-0.545\times10^{-18}\) J, option (C). \[ \boxed{\text{(C)}} \]
\(E_n=-\frac{2.18\times10^{-18}}{n^2}\) J.
Step 2: Substitute
For \(n=2\): \(E_2=\frac{-2.18\times10^{-18}}{4}=-0.545\times10^{-18}\) J. Option (C).
Final Answer:
\(E_2=-0.545\times10^{-18}\) J, option (C). \[ \boxed{\text{(C)}} \]
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