Question

If the conductivity of 0.08 M KCl solution is \( 2 \times 10^{-3} \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \), what is the molar conductivity of the solution?

• A. 350 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \)
• B. 250 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \)
• C. 25.0 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \)
• D. 0.25 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \)

Hint:

Molar conductivity can be calculated using the conductivity divided by the concentration of the solution.

Answer 1

The Correct Option is B

Step 1: Understanding molar conductivity.
Molar conductivity \( \Lambda_m \) is given by the formula: \[ \Lambda_m = \frac{\kappa}{C} \] Where \( \kappa \) is the conductivity and \( C \) is the concentration of the solution.
Step 2: Calculation.
Given that the conductivity is \( 2 \times 10^{-3} \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \) and the concentration is 0.08 M, the molar conductivity is: \[ \Lambda_m = \frac{2 \times 10^{-3}}{0.08} = 250 \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \] Step 3: Conclusion.
The correct answer is (B) 250 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \).