Step 1: Recall intensity formula in terms of magnetic field.
\[
I = \frac{c B_0^2}{2 \mu_0}
\]
where \(c = 3 \times 10^8 \, \text{m/s}, \, \mu_0 = 4 \pi \times 10^{-7} \, \text{H/m}, \, B_0 = 2.2 \times 10^{-4} \, \text{T}\).
Step 2: Substitute values.
\[
I = \frac{3 \times 10^8 \cdot (2.2 \times 10^{-4})^2}{2 \cdot 4 \pi \times 10^{-7}}
\]
Step 3: Compute square of B.
\[
B_0^2 = (2.2 \times 10^{-4})^2 = 4.84 \times 10^{-8}
\]
Step 4: Multiply by c and divide by \(2 \mu_0\).
\[
I \approx \frac{3 \times 10^8 \cdot 4.84 \times 10^{-8}}{2 \cdot 4 \pi \times 10^{-7}} \approx 5.8 \times 10^6 \, \text{W/m}^2
\]
Step 5: Verify units.
Units consistent as \(\text{W/m}^2\).
Step 6: Final conclusion.
\[
\boxed{5.8 \times 10^6 \, \text{W/m}^2}
\]