Step 1: Understanding the Question:
The question presents a homogenous second-degree equation representing a pair of straight lines passing through the origin. Given that the acute angle $\theta$ between these lines is $\frac{\pi}{4}$, we need to find the algebraic expression equivalent to the term $4h^2$.
Step 2: Key Formula or Approach:
The standard formula to compute the acute angle $\theta$ between a pair of straight lines given by $ax^2 + 2hxy + by^2 = 0$ is:
$$ \tan \theta = \left| \frac{2\sqrt{h^2 - ab}}{a + b} \right| $$
Step 3: Detailed Explanation:
We are given that the acute angle $\theta = \frac{\pi}{4}$. Substituting this value into our angle formula:
$$ \tan\left(\frac{\pi}{4}\right) = \left| \frac{2\sqrt{h^2 - ab}}{a + b} \right| $$
Since $\tan\left(\frac{\pi}{4}\right) = 1$, the equation becomes:
$$ 1 = \left| \frac{2\sqrt{h^2 - ab}}{a + b} \right| $$
To remove the absolute value bars and radical signs, let's square both sides of the equation:
$$ 1^2 = \frac{4(h^2 - ab)}{(a + b)^2} $$
Cross-multiplying the denominator to the left side gives:
$$ (a + b)^2 = 4(h^2 - ab) $$
Expanding the left side using the perfect square identity $(a+b)^2 = a^2 + 2ab + b^2$:
$$ a^2 + 2ab + b^2 = 4h^2 - 4ab $$
To isolate the target term $4h^2$, let's shift the $-4ab$ term from the right side over to the left side:
$$ 4h^2 = a^2 + 2ab + b^2 + 4ab $$
Combining the like terms ($2ab + 4ab = 6ab$) yields our final expression:
$$ 4h^2 = a^2 + 6ab + b^2 $$
Step 4: Final Answer:
The expression for $4h^2$ evaluates to $a^2 + 6ab + b^2$, which matches option (C).