Question:

If \(\sum_{r=0}^{n} \binom{n}{r} \frac{r + 3}{r} = \frac{3}{a+3}\), then \(a - n\) is equal to

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Match the closed form after simplifying binomial ratios.
Updated On: Mar 23, 2026
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The Correct Option is A

Solution and Explanation

Using \(\frac{\binom{n}{r} (r + 3)!}{(n-r)! (r+3)!}\) and summing gives \(\frac{3}{n+3}\).

Thus \(a = n \implies a - n = 0\).

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