Question:

If standard emf of cell \(\mathrm{Zn}_{(\mathrm{s})}\left|\mathrm{Zn}_{(\mathrm{1M})}^{+2}\right| \mathrm{Ag}_{(\mathrm{1M})}^{+1} \mid \mathrm{Ag}_{(\mathrm{s})}\) is 1.55 V .

What is electrical work done under standard conditions?

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Maximum electrical work equals \(-nFE^0\) for the cell reaction.
Updated On: Nov 13, 2026
  • -144.750 kJ
  • -193.00 kJ
  • -299.150 kJ
  • -386.00 kJ
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Electrical work done by a cell is \(W=\Delta G^0=-nFE^0_{\text{cell}}\).

Step 2: Find n
The cell reaction is \(\text{Zn}+2\text{Ag}^+\rightarrow\text{Zn}^{2+}+2\text{Ag}\), so \(n=2\).

Step 3: Calculation
\(\Delta G^0=-2\times96500\times1.55=-299150\text{ J}\)

Step 4: Convert to kJ
\(-299150\text{ J}=-299.150\text{ kJ}\)

Final Answer:
The electrical work done is -299.150 kJ. \[ \boxed{\text{(C) }-299.150\text{ kJ}} \]
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