Question:
If
\[
R(t) =
\begin{pmatrix}
\cos t & \sin t \\
-\sin t & \cos t
\end{pmatrix},
\]
then \(R(s)R(t)\) equals
If
\[ R(t) = \begin{pmatrix} \cos t & \sin t \\ -\sin t & \cos t \end{pmatrix}, \]
then \(R(s)R(t)\) equals
\[ R(t) = \begin{pmatrix} \cos t & \sin t \\ -\sin t & \cos t \end{pmatrix}, \]
then \(R(s)R(t)\) equals
Show Hint
Rotation matrices add angles under multiplication.
Updated On: Mar 23, 2026
- \(R(s+t)\)
- \(R(s-t)\)
- \(R(s)+R(t)\)
- None of these
Show Solution
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The Correct Option is A
Solution and Explanation
Rotation matrices satisfy:
R(s)R(t)=R(s+t).
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