Step 1: Concept pH is defined as $-\log_{10}[H_3O^+]$. Thus, $[H_3O^+] = 10^{-pH}$.
Step 2: Meaning Initial $[H_3O^+]_1 = 10^{-4} \text{ M}$. Final $[H_3O^+]_2 = 10^{-5} \text{ M}$.
Step 3: Analysis Ratio $= \frac{10^{-5}}{10^{-4}} = 10^{-1} = 1/10$.
Step 4: Conclusion The concentration becomes one-tenth of the original, meaning it decreases by 10 times.
Final Answer: (D)