Question:

If osmotic pressure of $0.2 \text{ M}$ aqueous glucose solution is $5 \text{ atm}$ at $300 \text{ K}$. Calculate the concentration of glucose solution having osmotic pressure $2.5 \text{ atm}$ at same temperature.

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At constant T: $\pi \propto C$
Updated On: May 8, 2026
  • $0.1 \text{ M}$
  • $0.05 \text{ M}$
  • $0.75 \text{ M}$
  • $0.25 \text{ M}$
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The Correct Option is A

Solution and Explanation


Concept: \[ \pi = CRT \Rightarrow \pi \propto C \quad (\text{T constant}) \]

Step 1:
Set ratio. \[ \frac{\pi_1}{\pi_2} = \frac{C_1}{C_2} \]

Step 2:
Substitute values. \[ \frac{5}{2.5} = \frac{0.2}{C_2} \] \[ 2 = \frac{0.2}{C_2} \]

Step 3:
Solve. \[ C_2 = \frac{0.2}{2} = 0.1 \]

Step 4:
Conclusion.
Concentration = $0.1 \text{ M}$ Final Answer: Option (A)
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