Question:
If \(\operatorname{Ln}\) represents lanthanoid element find the general formula of lanthanoid hydroxide.
If \(\operatorname{Ln}\) represents lanthanoid element find the general formula of lanthanoid hydroxide.
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Lanthanoids mainly show the +3 oxidation state, so the hydroxide has three hydroxide ions per metal ion.
Updated On: Nov 13, 2026
- \(\mathrm{Ln}(\mathrm{OH})\)
- \(\mathrm{Ln}(\mathrm{OH})_{2}\)
- \(\mathrm{Ln}(\mathrm{OH})_{3}\)
- \(\mathrm{Ln}(\mathrm{OH})_{4}\)
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
The most common and stable oxidation state of lanthanoids is +3.
Step 2: Balance the charge
\(\text{Ln}^{3+}\) combines with \(\text{OH}^{-}\) in the ratio 1 : 3.
Step 3: Result
The general formula is \(\text{Ln(OH)}_3\).
Final Answer:
The formula is \(\text{Ln(OH)}_3\). \[ \boxed{\text{(C) }\mathrm{Ln}(\mathrm{OH})_{3}} \]
The most common and stable oxidation state of lanthanoids is +3.
Step 2: Balance the charge
\(\text{Ln}^{3+}\) combines with \(\text{OH}^{-}\) in the ratio 1 : 3.
Step 3: Result
The general formula is \(\text{Ln(OH)}_3\).
Final Answer:
The formula is \(\text{Ln(OH)}_3\). \[ \boxed{\text{(C) }\mathrm{Ln}(\mathrm{OH})_{3}} \]
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