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if mathrm re 1 iy 3 26 where y is a real number th
Question:
If \( \mathrm{Re}(1+iy)^3 = -26 \), where \(y\) is a real number, then the value of \( |y| \) is
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When dealing with powers of complex numbers, expand step-by-step and separate real and imaginary parts clearly.
KEAM - 2015
KEAM
Updated On:
May 8, 2026
\(2\)
\(3\)
\(4\)
\(6\)
\(9\)
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The Correct Option is
B
Solution and Explanation
Concept:
To find the real part of a complex expression, expand it and collect real terms. Use: \[ (a+ib)^2 = a^2 - b^2 + 2iab \]
Step 1: Expand the expression
\[ (1+iy)^2 = 1 - y^2 + 2iy \] Now multiply by \( (1+iy) \): \[ (1+iy)^3 = (1 - y^2 + 2iy)(1+iy) \]
Step 2: Multiply carefully
\[ = (1 - y^2)(1+iy) + 2iy(1+iy) \] \[ = (1 - y^2) + i y(1 - y^2) + 2iy + 2i^2 y^2 \] \[ = (1 - y^2) + iy(1 - y^2 + 2) - 2y^2 \] \[ = (1 - y^2 - 2y^2) + i y(3 - y^2) \] \[ = (1 - 3y^2) + i y(3 - y^2) \]
Step 3: Extract real part
\[ \mathrm{Re}(1+iy)^3 = 1 - 3y^2 \]
Step 4: Use given condition
\[ 1 - 3y^2 = -26 \] \[ 3y^2 = 27 \] \[ y^2 = 9 \]
Step 5: Final value
\[ |y| = 3 \] \[ \boxed{3} \]
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