Question:

If 'l' is the length of the open pipe, 'r' is the internal radius of the pipe and 'V' is the velocity of sound in air then fundamental frequency of open pipe is

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Physics Tip : Remember that an open pipe has two open ends, so you must apply the end correction ($0.6r$) twice.
Updated On: Apr 23, 2026
  • $\frac{V}{(l+0.3r)}$
  • $\frac{V}{(l+1.2r)}$
  • $\frac{V}{(l+0.6r)}$
  • $\frac{V}{2(l+1.2r)}$
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The Correct Option is D

Solution and Explanation

Concept: Physics (Waves) – Fundamental Frequency and End Correction of an Open Pipe.

Step 1:
Calculate the effective length with end correction. For an open organ pipe, end correction ($e$) occurs at both ends. The effective length $L$ is: $$L = l + 2e$$ Given that $e = 0.6r$ for one end, the total correction is $2 \times 0.6r = 1.2r$. $$L = l + 1.2r$$

Step 2:
State the fundamental frequency formula. The fundamental frequency $f$ of an open pipe is given by: $$f = \frac{V}{2L}$$

Step 3:
Substitute the effective length. Substituting $L = l + 1.2r$ into the frequency formula: $$f = \frac{V}{2(l + 1.2r)}$$ $$ \therefore \text{The fundamental frequency is } \frac{V}{2(l+1.2r)}. $$
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