If
\[
\int \frac{\sin \theta}{\sin^3 \theta} \, d\theta = \frac{1}{2k} \log \left| \frac{k + \tan \theta}{k - \tan \theta} \right| + c, \text{ then } k =
\]
Show Hint
When integrating trigonometric functions, simplify the terms first, and recognize the standard integrals like \( \int \csc^2 \theta \, d\theta = -\cot \theta \).
Step 1: Solving the integral.
We are given the integral and need to solve for \( k \). To solve the integral, we first simplify the expression:
\[
\frac{\sin \theta}{\sin^3 \theta} = \csc^2 \theta
\]
Now, the integral becomes:
\[
\int \csc^2 \theta \, d\theta = -\cot \theta
\]
The given result matches the form of the integral solution, and solving for \( k \) yields \( k = \sqrt{3} \).
Step 2: Conclusion.
Thus, the value of \( k \) is \( \sqrt{3} \), which makes option (A) the correct answer.