Question:

If
\[ \int_0^a f(2a - x) \, dx = m \quad \text{and} \quad \int_0^a f(x) \, dx = n, \]
then
\[ \int_0^{2a} f(x) \, dx \]
is equal to:

Show Hint

Use substitution x→ a+b-x in definite integrals.
Updated On: Mar 23, 2026
  • \(2m+n\)
  • \(m+2n\)
  • \(m-n\)
  • m+n
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1:
\[ \int_0^{2a} f(x) \, dx = \int_0^a f(x) \, dx + \int_a^{2a} f(x) \, dx \]
Step 2: Let \(x = 2a - t\) in the second integral:
\[ \int_a^{2a} f(x) \, dx = \int_0^a f(2a - t) \, dt = m \]
Step 3:
\[ \int_0^{2a} f(x) \, dx = n + m \]
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