Question

If in the English alphabet, every even letter beginning from B is replaced by odd number beginning with 3, which letter/number will be the third to the right of the tenth number/letter counting from your right?

• A. M
• B. S
• C. 11
• D. None of these

Hint:

Always rewrite the full modified sequence before counting positions—it avoids confusion.

Answer 1

The Correct Option is B

Concept: This problem involves:

• Replacing even-position letters with odd numbers
• Counting positions from the right side

Step 1:Write the alphabet with positions: \[ A(1), B(2), C(3), D(4), \ldots, Z(26) \]
Step 2:Replace even-position letters: \[ B(2)\rightarrow 3,\; D(4)\rightarrow 5,\; F(6)\rightarrow 7,\; \ldots,\; Z(26)\rightarrow 27 \] So sequence becomes: \[ A, 3, C, 5, E, 7, G, 9, I, 11, K, 13, M, 15, O, 17, Q, 19, S, 21, U, 23, W, 25, Y, 27 \]
Step 3:Count from the right.
10th element from right: \[ 27(1), Y(2), 25(3), W(4), 23(5), U(6), 21(7), S(8), 19(9), Q(10) \] So, 10th from right = Q
Step 4:Move 3 to the right: \[ Q \rightarrow S \]
Step 5:Final Answer: \[ \text{S} \]