This question hides a simple substitution: each letter of CLEVER has been swapped for its mirror-image letter in the alphabet, the letter the same number of steps from the end as the original is from the start (A pairs with Z, B with Y, and so on). Checking this against CLEVER becoming XOVEVI confirms it: C pairs with X, L pairs with O, E pairs with V, V pairs with E, E pairs with V, and R pairs with I, all consistent mirror pairs.
Writing out the full mirror-pairing table makes it easy to encode any word: A-Z, B-Y, C-X, D-W, E-V, F-U, G-T, H-S, I-R, J-Q, K-P, L-O, M-N, and the same pairs read the other way. Applying this table to each letter of SMART: S pairs with H, M pairs with N, A pairs with Z, R pairs with I, and T pairs with G. Reading these off in order gives H, N, Z, I, G.
Following the mirror-pairing table letter by letter for S, M, A, R, T, in that order gives HNZIG.
Therefore, the correct answer is HNZIG.
This code swaps each letter for the one the same number of steps from the opposite end of the alphabet, so imagine one pointer starting at A and moving forward while a second pointer starts at Z and moves backward at the same pace; whatever letter the first pointer reaches, the second pointer marks its code. Checking this against the given example, Clever becomes XOVEVI: moving both pointers together, C (3rd from the front) lines up with X (3rd from the back), L (12th from front) lines up with O (12th from back), E (5th from front) lines up with V (5th from back), and R (18th from front) lines up with I (18th from back). The pairing holds for every letter, confirming the two-pointer idea.
Applying the same two moving pointers to SMART: S is the 19th letter from the front, so its pair is the 19th letter counting back from Z, which lands on H. M is the 13th from the front, pairing with the 13th from the back, N. A is the 1st from the front, pairing with the 1st from the back, Z. R is the 18th from the front, pairing with the 18th from the back, I. T is the 20th from the front, pairing with the 20th from the back, G. Reading these off in the order S, M, A, R, T gives H, N, Z, I, G.
Tracking two pointers moving inward from opposite ends of the alphabet together confirms SMART is coded as HNZIG.
Therefore, the correct answer is HNZIG.
In the following question, a group of numerals is given followed by four groups of symbol/letter combinations lettered (A), (B), (C), and (D). Numerals are to be coded as per the codes and conditions. You have to find out which of the combinations (A), (B), (C), and (D) is correct and indicate your answer accordingly.
| Numerals | 3 | 5 | 7 | 4 | 2 | 6 | 8 | 1 | 0 | 9 |
|---|---|---|---|---|---|---|---|---|---|---|
| Letter/symbol code | B | E | A | @ | F | K | % | R | M |
Read the following information carefully to choose the best option for the question:
In the following question some capital alphabets are written in a row, below them their coding has been given.
In the question, a particular word has been coded in a particular manner using codes as given below the capital letters.
You have to understand the pattern of coding and have to answer the question asked subsequently.
| A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| U | a | 2 | v | b | w | 3 | t | 4 | x | s | y | 5 | z | 6 | c | d | 8 | 7 | e | r | h | 9 | l | p | m |
Table 1: Character Mapping Table