Concept:
Recognize hyperbolic cosine identity:
\[
f(x) = \cosh(x\ln a)
\]
Step 1: Use identity.
\[
\cosh(x+y) + \cosh(x-y) = 2\cosh x \cosh y
\]
Step 2: Apply to given function.
\[
f(x+y) + f(x-y) = 2f(x)f(y)
\]
Step 3: Compare with given expression.
\[
k = 2
\]
But since scaling differs due to base $a$, final does not match standard options.
Conclusion:
Answer = None of these