Given: Two fair sixβfaced dice are thrown. Let the sum of numbers be \(X\). We want: \[ P(7 < X < 10) \] So the possible integer values of \(X\) are: \[ X = 8, 9 \] Total possible outcomes: Each die has 6 faces β total = \(6 \times 6 = 36\).
Favourable outcomes:
\[ (2,6), (3,5), (4,4), (5,3), (6,2) \] Total = **5 outcomes**
\[ (3,6), (4,5), (5,4), (6,3) \] Total = **4 outcomes**
Probability: \[ P(7 < X < 10) = \frac{9}{36} = \frac{1}{4} = 0.25 \]
| Year | Price of Apple | Quantity of Apple | Price of Banana | Quantity of Banana |
| 2010 | 1 | 100 | 2 | 50 |
| 2011 | 1 | 200 | 2 | 100 |
| 2012 | 2 | 200 | 4 | 100 |
, 0, π₯ β₯ 0 otherwise , 