Question:

If \( \Delta = \begin{vmatrix}1& 2& 3 \\ 2& 3& 5 \\ 3& 6& 12\end{vmatrix} \) and \( \Delta' = \begin{vmatrix}4& 8& 15 \\ 3& 6& 12 \\ 2& 3& 5\end{vmatrix} \), then

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Track row operations carefully: swaps change sign, scaling multiplies determinant.
Updated On: May 8, 2026
  • \( \Delta' = 2\Delta \)
  • \( \Delta' = -2\Delta \)
  • \( \Delta' = \Delta \)
  • \( \Delta' = -\Delta \)
  • \( \Delta' = 3\Delta \)
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The Correct Option is B

Solution and Explanation

Concept: Use determinant properties:
• Row interchange changes sign
• Multiplying row multiplies determinant

Step 1: Compare matrices

Observe \( \Delta' \) rows are rearranged and scaled.

Step 2: Reorder rows

Swap rows to match structure → introduces sign change.

Step 3: Identify scaling

First row is roughly 2 times original row.

Step 4: Combine effects

Scaling factor = 2 Row swap factor = -1 \[ \Delta' = -2\Delta \]

Step 5: Final answer

\[ \boxed{-2\Delta} \]
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