Question

If concentration of reactant ' \(A\) ' is increased by 10 times, rate of reaction increases 100 times. What is order of reaction if rate law is \(r=k[A]^x\) ?

• A. 1
• B. 1.5
• C. 2
• D. 3

Hint:

Compare the rate expression before and after the concentration change.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
For \( r=k[A]^x \), changing the concentration by a factor \( n \) changes the rate by \( n^x \).

Step 2: Set Up
\( \dfrac{r_2}{r_1}=\left(\dfrac{10[A]}{[A]}\right)^x=10^x \)

Step 3: Solve
\( 10^x=100=10^2 \), so \( x=2 \).

Step 4: Compare the options
The order is 2, option (C).

Final Answer:
The order of the reaction is 2. \[ \boxed{\text{(C) }\text{2}} \]