Question

If compressibility factor of real gas is 1.05 at STP. What is molar volume of real gas?

• A. $22.40\text{dm}^3$
• B. $21.33\text{dm}^3$
• C. $23.52\text{dm}^3$
• D. $23.05\text{dm}^3$

Hint:

$Z > 1$ means the real gas occupies more space than an ideal gas (repulsive forces dominate). Simply multiply 22.4 by $Z$.

Answer 1

The Correct Option is C

Step 1: Concept
The compressibility factor ($Z$) is defined as the ratio of the molar volume of a real gas ($V_{real}$) to the molar volume of an ideal gas ($V_{ideal}$) at the same T and P. $Z = V_{real} / V_{ideal}$

Step 2: Meaning
At STP (Standard Temperature and Pressure), the molar volume of an ideal gas is $22.4 \text{ dm}^3$.

Step 3: Analysis
$1.05 = V_{real} / 22.4 \text{ dm}^3$ $V_{real} = 1.05 \times 22.4$ $V_{real} = 23.52 \text{ dm}^3$

Step 4: Conclusion
The molar volume of the real gas is $23.52 \text{ dm}^3$. Final Answer: (C)