To find the value of $\beta$ in a bipolar junction transistor (BJT), we use the relationship between the emitter current ($I_E$), base current ($I_B$), and collector current ($I_C$). The formula is given by:
$I_E = I_C + I_B$
The current gain $\beta$ is defined as the ratio of the collector current to the base current:
$\beta = \frac{I_C}{I_B}$
Since $I_B = I_E - I_C$, we can substitute this into the equation for $\beta$:
$\beta = \frac{I_C}{I_E - I_C}$
Given that an increase in the emitter current by $4 \, \text{mA}$ results in an increase in the collector current by $3.5 \, \text{mA}$, the changes in respective currents are:
Assuming the transistor is operating in active mode, and the changes in current are proportionate, the change in equations can be used:
$\Delta I_E = \Delta I_C + \Delta I_B$
Using the known values:
$4 \, \text{mA} = 3.5 \, \text{mA} + \Delta I_B$
Rearranging gives:
$\Delta I_B = 4 \, \text{mA} - 3.5 \, \text{mA} = 0.5 \, \text{mA}$
Now we can find $\beta$:
$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{3.5 \, \text{mA}}{0.5 \, \text{mA}} = 7$
Thus, the correct answer is 7.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Semiconductors are a crystalline solid materials, whose electrical conductivity lies between a conductor and an insulator. Semiconductors are mainly used in the manufacturing of electronic devices like capacitors, transistors, diodes, Integrated circuits, etc.