Step 1: Concept
If a line makes angles $\alpha, \beta, \gamma$ with the coordinate axes, then their direction cosines $l = \cos\alpha$, $m = \cos\beta$, $n = \cos\gamma$ satisfy the identity $l^2 + m^2 + n^2 = 1 \implies \cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1$.
Step 2: Meaning
We are given $\alpha = 45^\circ$ and $\beta = 60^\circ$. We need to find the acute angle $\gamma$.
Step 3: Analysis
Substituting the given angles:
\[ \cos^2 45^\circ + \cos^2 60^\circ + \cos^2 \gamma = 1 \]
\[ \left(\frac{1}{\sqrt{2}}\right)^2 + \left(\frac{1}{2}\right)^2 + \cos^2 \gamma = 1 \]
\[ \frac{1}{2} + \frac{1}{4} + \cos^2 \gamma = 1 \]
\[ \frac{3}{4} + \cos^2 \gamma = 1 \implies \cos^2 \gamma = 1 - \frac{3}{4} = \frac{1}{4} \]
Since we need the acute angle, we take the positive root:
\[ \cos\gamma = \frac{1}{2} \implies \gamma = 60^\circ \]
Step 4: Conclusion
The acute angle the line makes with the $z$-axis is $60^\circ$.
Final Answer: (A)