Question:

If a fair coin is tossed 8 times, then the probability of getting at most 2 heads is...

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Add the binomial probabilities for 0, 1 and 2 heads.
Updated On: Oct 1, 2026
  • \(\frac{37}{64}\)
  • \(\frac{37}{256}\)
  • \(\frac{37}{128}\)
  • \(\frac{37}{512}\)
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The Correct Option is B

Solution and Explanation

Step 1: Setup
\(n=8\), \(p=\frac12\). \(P(X=r) = {}^8C_r\left(\frac12\right)^8\).

Step 2: Add up
\({}^8C_0+{}^8C_1+{}^8C_2 = 1+8+28 = 37\).

Step 3: Result
\(P(X\le2) = \frac{37}{256}\). Option (B).

Final Answer:
The probability is 37/256. \[ \boxed{\text{(B)}\ \frac{37}{256}} \]
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