If a diploid cell is treated with colchicine then it becomes
The correct option is (A) : Triploid
Colchicine prevents the development of microtubules necessary for the growth of spindle fibers. To split the chromosomes in a parental cell into two daughter cells evenly, spindle fibers are required. The genetic material won't be disseminated to the two freshly growing cells if microtubules aren't produced. As a result, the metaphase stage will see a decrease in the production of new cells, and the diploid cell will divide into tetraploid cells with four chromosomes instead of two.
| Pair of skeletal parts | Category | |
|---|---|---|
| (a)$\,\,$ | Sternum and ribs$\,\,$ | Axial skeleton |
| (b)$\,\,$ | Clavicle and glenoid cavity$\,\,$ | Pelvic girdle |
| (c)$\,\,$ | Flumerus and ulna$\,\,$ | Appendicular skeleton |
| (d)$\,\,$ | Malleus and stapes$\,\,$ | Ear ossicles |
| List - I | List – II | ||
| A. | Chiasmata formation | i. | Pachytene |
| B. | Crossing over | ii. | Diakinesis |
| C. | Synaptonemal complex formation | iii. | Diplotene |
| D. | Terminalisation of chiasmata | iv. | Zygotene |
The sequence of growth and division of a cell, and consists of a series of biological processes, particularly the resting phase (G0), the interphase (G1, S, G2), and cell division (i.e. mitosis and cytokinesis)